Solve the alogrithm above you

#1

Ok, the concept is simple, first you solve the algorithm above you, then you give several inputs and their respective outputs using a new specific algorithm.

Rules:
1.) Be easy! If your algorithm isn’t simple enough, or isn’t logical, then no one will be able to solve it, and thus the thread will come to a hault.
2.) The algorithm doesn’t need to be your own, but you’re more than welcome to make up your own too.
3.) You MUST solve the algorithm above you before posting a new problem.
4.) If you can not solve an algorithm, you can ask the author for either a hint or more specific inputs, but someone needs to solve it before you go on.
5.) If you solve an algorithm, you aren’t required to make your own; the person who posts after you just won’t have to solve the previous one to post theirs.

Ok, here’s mine (input on left, output on right):


0 - 0
1 - 1
2 - 2
3 - 3
4 - 10
7 - 13
8 - 20
10 - 22
12 - 30
15 - 33
16 - 100
20 - 110
99 - 1203
100 - 1210
1000 - 33220
9999 - 2130033

CONVERTER PROGRAM HERE

Ok, so that’s a quick program I made in c++ earlier today. And no, I won’t post the sourcecode, for obvious reasons :wink:

#2

42

#3

Huh?
https://en.wikipedia.org/wiki/42_(number)
Is there something in there that I should be aware of?

#4

42 is The Answer to the Ultimate Question of Life, the Universe, and Everything
https://en.wikipedia.org/wiki/42_(number)#In_The_Hitchhiker.27s_Guide_to_the_Galaxy
:retard:

#5

It’s the Answer to Life, the Universe, and Everything.

edit: :ninja:ed :frowning:

#6

It is the ultimate answer to life, the universe, and everything.

EDIT: I actually did that on purpose…

#7

1 - 1 = A
2 - 2 = B
3 - 3 = C —> C is for cookie, thats good enough for me, cookie cookie cookie starts with c

#8

This really doesn’t work if you guys don’t try :wink:

#9

You put holes into your numbers on purpose

0 - 0
1 - 1
2 - 2
3 - 3
4 - 10
5 - 11
6 - 12
7 - 13
8 - 20
9 - 21
10 - 22
11 - 23
12 - 30
13 - 31
14 - 32
15 - 33
16 - 100
17 - 101
18 - 102
19 - 103
20 - 110

Maybe there’s a formula, but I’m getting it wrong.

Am I on the right track?

This forum game, I actually like!

Close?
y = x + 7*[ (x-1) div 3] + 70*[(x-1) div 15]

Some more thought…
y = x + 6*[ x div 4] + 70*[x div 16]

Ooops!
y = x + 6*[ x div 4] + 60*[x div 16]

Therefore
y = x + 6*[ x div 4] + 60*[x div 16] + 600*[x div 256] + 6000*[x div 65536] …
or
y = x + 6*[ x div 4] + 60*[x div 16] + 600*[x div 64] + 6000*[x div 256] + 60000*[x div 1024]…

Maybe there’s a shorthand way to write that…

#10

I dunno what ‘holes’ are, but sadly, no, you’re not on the right track.
You’re gonna smile when you see what the algorithm is :slight_smile:
Thanks for genuinely trying, too!

Oh, if ‘holes’ are incorrect or false data, then no; I haven’t put up any incorrect data.

Edit:
OOOOOOOOOOOOOOOOOOOOOOOOOOH
ROFL
By ‘holes’ you meant I skipped some input numbers. Yes, yes of course, I was giving some random numbers.

And yes, now you’re on the right track :slight_smile:

#11

Well you posted while I was editing, so here’s a bump

y = x + 6*[ x div 4] + 60*[x div 16]

x is input
y is output
[a div b] is a/b rounded down to the nearest integer

it works

#12

I’m afraid that doesn’t work with my newest number added to the input, which is 100.
But you definitely have the right idea.

Edit: also added 1000 and 9999

also added 99 which destroys your 2 digit algorithm, sorry mate.

#13

Haha, no problem thanks for giving more info. I’m busy now, but I’ll give it another shot when I can.

#14

Yeah, that’s wonderful, I wish you the best of luck!
I’m gonna write a program to calculate the output based on an input based on the algorithm so you can have unlimited examples. (if no one solves it before then)

#15

I thought you said be easy! Ugh… I’ve noticed a few patterns here and there, but can’t come up with a consistent one. I think I’ll post “42” like everyone else and come back to it later.

Oh, and please please please PLEASE add a loop to that program. I only used it 4 or 5 times and it drove me nuts that it didn’t even have a simple loop.

#16

Lol, ok fair enough. I fixed it, it’s already uploaded :wink:

Something like:


While (true)
{
//code[…]
}

#17

brb decompilin :stuck_out_tongue_winking_eye:

Edit: doh… c++ and windows executable :frowning: where’s mah *nix-executable… :’( ?

#18

Needs some Kramer’s Law up in here.

Seriously though, be easy?

#19

Fine, I can’t believe no one got it, but here’s a HUGE hint:
I’m converting to a certain base, from base 10.

#20

That would be base 4 then. Kinda embarrassed that I didn’t see that.

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