He has used the terms “HALOS files” and “the non-Hex code”–although, I think the latter was simply in regard to the plaintext version of the ciphertext.
Interesting, indeed. :whistling:
it was a matter of time until I hit it, I know ive annoyed many of you…so to make up for it, I give you this.
RELATIVE ATOMIC MASS. or atomic weight… and the SAGE COMPUTER IN WASHINGTON AND E8 LIE COMPUTATION.I invite you to check everything ive put here and you will see we got it…FINALLY…
zirconium, its RELATIVE ATOMIC MASS IS .= 91.224 PIZZA. IT WAS A HINT AT WHAT TO DO TO THE NIOBIUM ISOTOPES…
the niobium isotopes, we need to do the math on it. 21 into 1, is likely referring to the fraction based off of carbon-12here is the equation that needs to be applied to the niobium isotopes… (see below.) I didn’t look up the KEV stuff, someone who knows math or physics can do that part, but we have to solve that equation guys…this will be long, so read it before you judge… (pointless, big hug for you)
2nd message that was in the hint he left with the 21 into 1, was SAGE. at first I thought it was the SEMI-AUTOMATIC GROUND ENVIRONMENT SYSTEM, I WAS WRONG.
it was the SAGE computer in Washington.here you can read all about it, it tells a great story and it explains how they got to the end of the computation, and what was done to do it. the basically cut it up into pieces, also you have to add the TIME it took to put it together…
https://www.liegroups.org/talks/E8TALK.pdfyou see that number247… guess what,
In mathematics, E[sub]8[/sub] is any of several closely related exceptional simple Lie groups, linear algebraic groups or Lie algebras of dimension 248 LIE!!! so maybe that 248th dimension is xen? in game lore anyhow…
you wanted to know what that octodog thingy was? pretty sure it was a hint at the inverse of this number. think of those pizzas as zeros…so we had 0 octodog 0 or 080… OR Every octonion is a real linear combination of the unit octonions: take a look at the number
below…there is ALOT on these LIE,
computations, and there is this…en.wikipedia.org/wiki/Octonion octonion…O OCTO O? HINT?
the big brain behind that was Marius Sophus Lie but the actual e8 computation was not completed until jan
At 9a.m .on January 8,2007,a c omputer finished writing sixty gigabytes of files:Kazhdan-Lusztigpolynomialsforthe splitrealgroup G®of type E8.Their values at 1 are coefficients in irreducible characters of G®.The biggest coefficient was 11,808,808,in!!!
catch up and read about it here as well. https://www.aimath.org/E8/E8release.txt
FOR ALL THE INFO ON THIS COMPUTATION, GO HERE…
https://www.aimath.org/E8/ There are also tools on the site you can use.
you can download all the numbers in sections, also they have a program for several operating systems with pre compiled information…so you guys that know how to do that stuff, you 'll love this…
I also attached a txt file that you can look at and take a look at some of the numbers, here is also a larger equation, that any of the devs that worked on this might be familiar with…
how they wrote down 453060x453060 matrix.
152q22+3472q21+38791q20+293021q19 +1370892q18+4067059q17+7964012q16+11159003q15 +11808808q14+9859915q13+6778956q12+3964369q11 +2015441q10+906567q9+363611q8+129820q7 +41239q6+11426q5+2677q4+492q3+61q2+3qItsvalueat1is60,779,787
short timeline,11/06 Experiments by BirneBinegar on William Stein’s computer SAGE showed we needed 150G. 11/28/06 Asked about pure math uses for 256G computer. 11/30/06 NoamElkies told us we didn’t need one…one 150G computation(modular arithmetic) −−−−−−−→four 50G computations12/03/06 Marc van Leeuwen made Fokko’s code modular. 12/19/06 mod 251 computation on sage.Took17hours:Total elapsed time=62575s. Finished at l=64,y=453059d store.size()=1181642979,primsize=3393819659VmData:64435824kB
Writing to disk took two days.Investigating why output bug,so mod 251 character table no good. check the link for the rest of it…notice the times though, when they got it right, they are important. time DOES reveal all things.
so go on, someone that knows math and this stuff…THIS IS WHAT WE NEED. don’t believe me? JUST LOOK UP WHAT I POSTED.
read on.
https://en.wikipedia.org/wiki/Lie_group group theory…
The atomic weight of an element depends on the abundance of its isotopes. If you know the mass of the isotopes and the fractional abundance of the isotopes, you can calculate the element’s atomic weight. The atomic weight is calculated by adding the mass of each isotope multiplied by its fractional abundance. For example, for an element with 2 isotopes:
atomic weight = massa x fracta + massb x fractb
If there were three isotopes, you would add a ‘c’ entry. If there were four isotopes, you’d add a ‘d’, etc.
Atomic Weight Calculation Example
If chlorine has two naturally-occurring isotopes where:
Cl-35 mass is 34.968852 and fract is 0.7577Cl-37 mass is 36.965303 and fract is 0.2423
atomic weight = massa x fracta + massb x fracb
atomic weight = 34.968852 x 0.7577 + 36.965303 x 0.2423
atomic weight = 26.496 amu + 8.9566 amu
atomic weight = 35.45 amu
Tips for Calculating Atomic Weight•The sum of the fractional abundance values must equal 1.•Be sure to use the mass or weight of each isotope and not its mass number.
in including a picture I made with the grilled pizza.jpg, its not the finished product, but you can see where I’m going with it and read about it here…
https://en.wikipedia.org/wiki/An_Exceptionally_Simple_Theory_of_Everything
these books may be helpful…
IUPAC books
1 General
2 Blue Book
3 Gold Book
4 Green Book
5 Orange Book
6 Purple Book
7 Red Book
8 Silver Book
9 White Book
10 See also
11 References
12 External links
e8(one innerclass both simply connected and adjoint).txt (2.29 KB)
swapped and stacked.txt (906 Bytes)
I don’t know how I could make it any easier
start with relative atomic mass, look up the relative atomic mass number for zirconium… which is right next to niobium… 91.224 it was a hint…
I posted the equation how to solve that…
the go to the code we got with the niobium isotopes,… AND SOLVE IT WITH THE EQUATION. all the information that was posted with the isotopes…is exactly the information you need to run that equation,
just look up the references I posted. and read it piece by piece.
I have a high school education man, if I can understand this, anyone that has actually studied should breeze right through this if they read piece by piece. [EDIT] this was not meant as a negative comment. It will take me forever to do this, the smarter people that, I was implying should be able to knock this out no sweat.
we have also been mislead on occasion… the voice of the people is the voice of god… read the first part of that quote that was NOT posted… TRUST NO ONE.////
Nec audiendi qui solent dicere, Vox populi, vox Dei, quum tumultuositas vulgi semper insaniae proxima sit
I think you are forcing way too much thinking into this ARG, mate.
It’s a puzzle, not a murder mystery.
You would think Storm would actually make it that hard to solve?
I think we are missing something we overlooked in the game so far.
…LOOOOOOOK…
95Nb 41 54 94.9068358(21) 34.991(6) d ß- 95Mo 9/2+
95mNb 235.690(20) keV 3.61(3) d IT (94.4%) 95Nb 1/2-
ß- (5.6%) 95Mo
96Nb 41 55 95.908101(4) 23.35(5) h ß- 96Mo 6+
97Nb 41 56 96.9080986(27) 72.1(7) min ß- 97Mo 9/2+
97mNb 743.35(3) keV 52.7(18) s IT 97Nb 1/2-
98Nb 41 57 97.910328(6) 2.86(6) s ß- 98Mo 1+
98mNb 84(4) keV 51.3(4) min ß- (99.9%) 98Mo (5+)
IT (.1%) 98Nb
99Nb 41 58 98.911618(14) 15.0(2) s ß- 99Mo 9/2+
99mNb 365.29(14) keV 2.6(2) min ß- (96.2%) 99Mo 1/2-
IT (3.8%) 99Nb
100Nb 41 59 99.914182(28) 1.5(2) s ß- 100Mo 1+
100mNb 470(40) keV 2.99(11) s ß- 100Mo (4+,5+)
101Nb 41 60 100.915252(20) 7.1(3) s ß- 101Mo (5/2#)+
102Nb 41 61 101.91804(4) 1.3(2) s ß- 102Mo 1+
102mNb 130(50) keV 4.3(4) s ß- 102Mo high
103Nb 41 62 102.91914(7) 1.5(2) s ß- 103Mo (5/2+)
104Nb 41 63 103.92246(11) 4.9(3) s ß- (99.94%) 104Mo (1+)
these are the numbers for zirconium…
[table]
[tr]
[td] Atomic number[/td]
[td]40[/td]
[td] Relative atomic mass[/td]
[td]91.224[/td]
[/tr]
[/table]
Nb ATOMIC NUMBER IS 41…
now for all the neh sayers…
here is the link… https://sporadic.stanford.edu/bump/sagedays/lie.pdf
look at this image…
LOOK AT WHAT THE PAPER IS CALLED…
LOOK WHATTHAT THING ON THE LEFT LOOKS LIKE… MAYBE A SLICE O PIZZA? AND WOW…WHAT IS THAT AT THE TOP? A LAMBDA SYMBOL…
BOOOM…
https://www.liegroups.org/dissemination/spherical/explorer/cgi-bin/spherical.cgi
so lets shake hands and knock this out!!!
this puzzle hasn’t been solved for years with good reason…
when one of the most prestigious colleges’ pc guys start taking notice… the difficulty had to be upped…
the complexity of the whiteboards and attention to detail in game is staggering… why wouldn’t we have to do that level of mathematics to solve the puzzle its based on?
I actually read everything you just posted, @drgibbles, and tried really, really hard to understand where you were coming from. I really did.
But then my brain exploded like that handshake in that movie clip you posted.
It’s too much, man. At the very most, we may have to do some light decryption by hand, but everything up to this point has been solvable without melting one’s mind. I believe you have the right mind for delving into this mystery, but I think, for your sake and ours, you should scale it back a bit. Think more about how the pieces can fit together, and less about how you can use the pieces in various modes of operation.
I think you might be on to something @drgibbles. The Lie and Lamda can’t be a coincidence. But I’m not so sure on the math here. I think we need to ask ourselves what the “Pizza”, that Dr. Horn is referring to, really is. It may not be a pizza at all.
Side note: The picture on the ‘tempus omnia revelant’ page (the one with the guy holding pizza). His name is Anthony. It said on one of the whiteboards that Anthony keeps stealing Dr. Horn’s pizza. I’d upload the two photos but I’m too lazy right now
Drgibbles, even for me it is very difficult to read many of your posts and i am the one here that likes and understands science very well.
For god’s sake, the amount of gibberish in this post is unheard of. Not only are you throwing around big words without any idea of what they actually mean, as is made obvious by how cluelessly you’re writing up random pieces of information from whatever you’re referencing, but you didn’t even have the decency to construct a half-readable text. Here’s your post summed up:
21 into 1 -> Carbon-12
21 into 1 Hint -> SAGE (Anagram of AGES, presumably, otherwise another dumb mistake) -> SAGE computational array -> E8 mapping -> 248-dimensional Lie groups
Octodog -> Octonions
Some copy-pasted text from the fifth slide of the E8TALK, released by the Atlas group behind it, sprinkled with random spacings and punctuation.
Links to E8-related material.
Some more copy-pasted stuff about E8.
Link to Lie groups.
Equation to calculate atomic mass of elements from atomic mass of their isotopes in relation to their rarity, presumably copy-pasted from somewhere else as well.
Link to a unified field theory based on E8.
References to IUPAC books.
Never once, in the entirety of your post, have you drawn any sort of conclusionary point, regardless of its relation to HALOS, the ARG, or what have you. Your post is made up of various copy-pasted fragments of text, spiced with some incorrect punctuation and utterly confusing sentences added by yours truly. The topics you go over in your post are undergraduate-level mathematics, (Basic and advanced group theory, mostly. This is covered in Linear Algebra courses within the first few semesters, with the specifics regarding in-depth E8 research usually waiting until postgraduate status. I can only speak for the university I myself go to though.) and most certainly not part of high school education.
The only connections your post has to the ARG are “SAGE” and “Atomic mass of Niobium”;
- “SAGE” would be an anagram of the potential clue contained in the 21-into-1 message, as pointed out by Flavran. Not only is the likelihood of the unchanged “AGES” clue being relevant somewhat low, but the possibility that “SAGE” would be the correct anagram to go off of would be 1/23rd of that. Anyway, since your post is complete and utter nonsense, you probably didn’t even think so far, and simply mis-read what Flavrans said as “SAGE”.
- Your equation regarding the calculation of elemental atomic mass provides us with just that, a way to calculate elemental atomic mass. In no way does this tangent the goals of the ARG; The atomic mass of Niobium has been calculated as precisely 92.90638 Atomic Mass Units, give or take 0,00001 AMU due to random variance, and as such this equation is of no use at all to us.
In conclusion, your post is one huge pile of crap. You mention some big words here and there, but you clearly didn’t understand what you were copy-pasting, nor what you were writing about. Combine this with the lies you told about this being as easy as you can make it, and this being part of high school education, and it’s now safe to say you’re very clearly a troll looking for attention. Please refrain from posting in this thread until you’ve changed your mind on whether or not you want to act like a little child.
If anyone in this thread is not convinced of drgibbles’ illegitimacy, please PM me and I can go into more detail regarding how his post is completely nonsensical from start to finish. There’s no need to continue spamming this thread with content that is clearly irrelevant to the ARG itself.
EDIT: Apologies for being mean, but especially after some somewhat recent events I have not taken a liking to trolls, and I’d like to see this puzzle solved sooner rather than later.
This is a place of ideas and reason. No need to start picking battles.
no problem… I will no longer post what I find. I gave you the answer as how to find out what the Nb MINDAT that was sent meant. i don’t think it was sent for no reason.
the “octonion” remark could be tied to the ONION information given on the cicada 3301 puzzles which I was just showing that some clues could be similar to clues that have been in other difficult puzzles. or may be based on or inspired by another puzzle , dogs and onions, they kind of go together. regardless, the 80808 NUMBER I posted was found with the lie computation. the parts that I cut and pasted was the formula for how the number 91.224 was reached, for zirconium and every other relative atomic weight. … all the information in the nb isotope information that was given, ARE THE EXACT NUMBERS YOU NEED TO FIND THE RAM… its a long equation. also, I did NOT re arrange the letters that flav put up. I ask you what do you think the pizza is? the 1/12 that I linked to carbon-12 is because that is what is used to find the RAM … its a ratio…1/12 . I did not post anything that I do not understand. I would not just cut and paste random information. if it is cut and paste, it is so you can either click on the link or you can read it verbatim. or you can see where I am getting the numbers from.
I gave you an answer as to what the pizza is and how i found that number. you don’t think its more than coincidence that for you to get the number 91.224 is by doing the equation i provided using the exact number sets that the niobium isotopes provided? , i gave you examples as to what the lie is. also, if i remember correctly, weren’t there images of pizza having 8 slices?
no worries though. i will keep it to myself from now on. best of luck
there are octodogs, like in game, and there are octonions, which is math related… people here, put onions on their hot dogs… the octodog, slices hotdogs…
the image is of 2 pizzas and an octodog… I personally get onions on my pizza, and my hotdogs… while looking up octodog, and lie information, I came across octonions…
there are other complex arg’s that actually brings up onions quite a bit…
@dondaldduck8
ill break it down for you so you understand better, it will be short and sweet… when people put out info like that, it just motivates me more. so no worries.
I’m calling it: our legitimate attempt at this thing has completely gone to shit.
I’ll contribute again once we get some clear, irrefutable evidence that this is moving forward. As of now, it just seems to be a way for people to get attention, and it is too frustrating to bother with the lunacy.
Just report drgibbles. Whether it was intentional or not, he/she has effectively derailed the conversation with the constant double posting and padded theories that lead nowhere.
I feel like what he has here is sound… if you can follow it. We don’t need to report him at all, just leave him off with a warning. Besides that, Storm or TextFAM would’ve come in to shut him down already(probably) if he was truly derailing our conversation with completely mindless drivel, as they’ve done before with error404notfound.
@drgibbles You need to slow down a bit there. Too much hype leaves people confused. Just make your posts short and articulate as possible without all the hype. I can tell you got a good lead going possibly with this, as a lot of your links make sense in the context of our ARG, but make sure to read them through before posting and try to give a summary for everyone or explain why it might be related on a much more than “IT HAS LIE IN IT” sense. Keep up the good research.
This is the only part that makes direct sense. The full Latin quote and translation, according to Oxford (via Wikipedia), goes:
Since Storm was the one who wrote that on the Tempus omnia revelant page, would the entire point of that line be “don’t listen to me”? or a warning against Wild Mass Guessing in the form of “the riotousness of the crowd”, which means us as players of this ARG?
If the former, then TOR is meant to disrupt us. Was it sent by HALOS in order to throw us off its scent? Possibly, since it has been successful in doing that for YEARS. WHO KNOWS if HALOS has managed to successfully escape and upload itself to the internet, where it can proliferate and stay basically invincible, thanks to this distraction.
Where did you get that whole thing from?